[SDL] Flickering and division by zero in Windows

[Tommy Hinks]

This will fail horribly in C, giving a NaN (Not a Number ) value.

In C++ the way to go is:

#include <climits>

float inf = std::numeric_limits<float>::max();

This gives the largest possibly representable float number. You could
use double instead and get an even larger number.

However, most times trying to actually represent infinity is a bad
idea. It's inherently a kind of glitch in mathematics, and even more
so in computers. Simply test if a denominator is zero and if so you
know that it is infinite. Use a bool or something to say that, not the
largest number you can possibly think of, it will only lead to grief.

Hope that helps.

/ Tommy

On 25/02/07, Andre de Leiradella <leiradella at bigfoot.com> wrote:
>
> > How would you express infinity in binary?
> >
> > Lilith
> >
> Using doubles (8-byte):
>
> +inf: 3f f0 00 00 00 00 00 00
> -inf: bf f0 00 00 00 00 00 00
>
> Or in C:
>
> pinf = 1.0 / 0.0;
> ninf = -1.0 / 0.0;
>
> Cheers,
>
> André
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